Diagnosis
You have entered characteristic value '&V1&' for characteristic '&V2&'.However, characteristic value '&V1&' does not fulfill the selectionconditions. These were stored in the planning package currently beingprocessed. It has the technical name '&V3&' .

System Response
The entry is not accepted.

Procedure
Overwrite '&V1&' with a valid characteristic value and check theselection conditions in the planning package with the technical name '
V3'. you can also solve the problem by deleting the data record withthe invalid characteristic value.