Diagnosis
For characteristic &V3& selection is defined by variable &V2&. But thevariable contains a further characteristic &V1&, which is not enteredin the level. If a selection should take place by a v ariable, then allcharacteristics from this variable must be contained in the level, andall characteristics contained in the variable must be selected withthis variable.

Procedure
There are two possibilities to make the level consistent again.

• Change the selection conditions for characteristic &V3& so that they do
not contain the variable &V2&.

• Add characteristic &V1& into the level and enter as selection,
replacement by variable &V2&.