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Diagnosis DataStore object &V1& has been designated as check object for the masterdata of characteristic &V3&. DataStore object &V1& must therefore havethe same key as the characteristic. Characteristic &V2& is in the key of the DataStore object, but not inthe compound of characteristic &V3& that needs to be checked. System Response This is only a warning - you are still able to activate characteristicV3. Procedure Add characteristic &V2& to the compound of characteristic &V3& or removethe characteristic from the key part of the DataStore object. |