Diagnosis
Characteristic &V2& references characteristic &V1&. It has the samemaster data table and the same attributes as characteristic &V1&.Therefore, characteristic &V2& cannot be used as an attribute withcharacteristic &V1&. If that were so, characteristic &V2& would be itsown attribute at the same time.

System Response
Characteristic &V1& cannot be activated.

Procedure
Take characteristic &V2& out of the attribute list for &V1&, or definea new characteristic with referencing to characteristic &V1&, and usethe new characteristic as an attribute of &V1&.